The degree of freedom and outline the ANOVA table with the sources of variance.

Question

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Answer 1

Question

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

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Answer 2

Question

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

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Answer 3

Question

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

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Answer 4

Question

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

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Answer 5

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

Answer 6

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

Answer 7

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

Answer 8

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

Answer 13

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

Answer 14

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

Answer 15

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

Answer 20

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

Answer 21

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

Answer 22

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

Answer 27

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

Answer 28

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

Answer 29

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.