
Concept explainers
To test: A regression to predict the

Answer to Problem 45E
Solution: The regression equation is
with
The ANOVA is given below:
Degrees of freedom |
Sum of Squares |
Mean sum of squares |
F-statistic |
P-value |
|
Regression |
1 |
2.1556 |
2.1556 |
12.89 |
0.001 |
Residual |
29 |
4.8499 |
0.1672 |
||
Total |
30 |
7.0055 |
Explanation of Solution
Calculation: To perform the
Step 1: Open the Minitab worksheet.
Step 2: Go to Stat > Regression > Regression.
Step 3: Select “
Step 4: Go to graph and select residual versus fits.
Step 5: Click “OK.”
The estimated regression equation is
with
Conclusion: Since the P-value is less than 0.05, the result is significant. The variation in the variable
To test: A regression to predict the

Answer to Problem 45E
Solution: The regression equation is
with
The ANOVA is given below:
Degrees of freedom |
Sum of Squares |
Mean sum of squares |
F-statistic |
P-value |
|
Regression |
1 |
3.0915 |
3.0915 |
22.91 |
0.000 |
Residual |
29 |
3.9140 |
0.1350 |
||
Total |
30 |
7.0055 |
Explanation of Solution
Calculation: To perform the regression analysis to predict
Step 1: Open the Minitab worksheet.
Step 2: Go to Stat > Regression > Regression.
Step 3: Select “
Step 4: Go to graph and select residual versus fits.
Step 5: Click “OK.”
The estimated regression equation is
with
Conclusion: Since the P-value is less than 0.05, the result is significant. The variation in the variable
To test: A regression to predict the

Answer to Problem 45E
Solution: The regression equation is
with
The ANOVA is given below:
Degrees of freedom |
Sum of Squares |
Mean sum of squares |
F-statistic |
P-value |
|
Regression |
2 |
3.1047 |
1.5524 |
11.14 |
0.000 |
Residual |
28 |
3.9008 |
0.1393 |
||
Total |
30 |
7.0055 |
Explanation of Solution
Calculation: To perform the regression analysis to predict
Step 1: Open the Minitab worksheet.
Step 2: Go to Stat > Regression > Regression.
Step 3: Select “
Step 4: Go to graph and select residual versus fits.
Step 5: Click “OK.”
The estimated regression equation is
with
Conclusion: Since the P-value is less than 0.05 for LTRAP, the result is significant for LTRAP. The variation in the variable
To test: A regression to predict the

Answer to Problem 45E
Solution: The regression equation is
with
The ANOVA is given below:
Degrees of freedom |
Sum of Squares |
Mean sum of squares |
F-statistic |
P-value |
|
Regression |
3 |
5.1494 |
1.7165 |
24.97 |
0.000 |
Residual |
27 |
1.8562 |
0.0687 |
||
Total |
30 |
7.0055 |
Explanation of Solution
Calculation: To perform the regression analysis to predict
Step 1: Open the Minitab worksheet.
Step 2: Go to Stat > Regression > Regression.
Step 3: Select “
Step 4: Go to graph and select residual versus fits.
Step 5: Click “OK.”
The estimated regression equation is
with
Conclusion: Since the P-value is less than 0.05, the result is significant. The variation in the variable
To test: A regression to predict the

Answer to Problem 45E
Solution: The Regression equation is
with
The ANOVA is given below:
Degrees of freedom |
Sum of Squares |
Mean sum of squares |
F-statistic |
P-value |
|
Regression |
2 |
5.0965 |
2.5483 |
37.38 |
0.000 |
Residual |
28 |
1.9090 |
0.0682 |
||
Total |
30 |
7.0055 |
Explanation of Solution
Calculation: To perform the regression analysis to predict
Step 1: Open the Minitab worksheet.
Step 2: Go to Stat > Regression > Regression.
Step 3: Select “
Step 4: Go to graph and select residual versus fits.
Step 5: Click “OK.”
The estimated regression equation is
with
Conclusion: Since the P-value is less than 0.05, the result is significant. The variation in the variable
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Chapter 11 Solutions
Introduction to the Practice of Statistics
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