What output will be produced by the following code? public class Demo { public static void main (String[] args) { System.out.println (“The output is:”); foo (23); System.out. println (); } public static void foo (int number) { if (number > 0) { foo (number / 2); System.out.print (number % 2); } } }

Question

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Answer 1

Textbook Question

Chapter 11, Problem 1E

What output will be produced by the following code?

public class Demo

{

public static void main (String[] args)

{

System.out.println (“The output is:”);

foo (23);

System.out. println ();

}

public static void foo (int number)

{

if (number > 0)

{

foo (number / 2);

System.out.print (number % 2);

}

Expert Solution & Answer

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

//Definition of main class

public static void main(String[] args)

{

//Print the statement

System.out.println("The output is:");

//Call the method "foo()"

foo(23);

//Print new line

System.out.println();

}

//Definition of method "foo"

public static void foo(int number)

{

//Check the condition

if (number > 0)

{

//Call the method "foo()"

foo(number / 2);

//Print the output

System.out.print(number % 2);

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.
• The method “foo()” is defined.
- ○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.
- ○ Print the result after determining “number%2”.

Sample Output

Output:

The output is:

10111

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Answer 2

Textbook Question

Chapter 11, Problem 1E

What output will be produced by the following code?

public class Demo

{

public static void main (String[] args)

{

System.out.println (“The output is:”);

foo (23);

System.out. println ();

}

public static void foo (int number)

{

if (number > 0)

{

foo (number / 2);

System.out.print (number % 2);

}

Expert Solution & Answer

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

//Definition of main class

public static void main(String[] args)

{

//Print the statement

System.out.println("The output is:");

//Call the method "foo()"

foo(23);

//Print new line

System.out.println();

}

//Definition of method "foo"

public static void foo(int number)

{

//Check the condition

if (number > 0)

{

//Call the method "foo()"

foo(number / 2);

//Print the output

System.out.print(number % 2);

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.
• The method “foo()” is defined.
- ○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.
- ○ Print the result after determining “number%2”.

Sample Output

Output:

The output is:

10111

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Answer 3

Textbook Question

Chapter 11, Problem 1E

What output will be produced by the following code?

public class Demo

{

public static void main (String[] args)

{

System.out.println (“The output is:”);

foo (23);

System.out. println ();

}

public static void foo (int number)

{

if (number > 0)

{

foo (number / 2);

System.out.print (number % 2);

}

Expert Solution & Answer

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

//Definition of main class

public static void main(String[] args)

{

//Print the statement

System.out.println("The output is:");

//Call the method "foo()"

foo(23);

//Print new line

System.out.println();

}

//Definition of method "foo"

public static void foo(int number)

{

//Check the condition

if (number > 0)

{

//Call the method "foo()"

foo(number / 2);

//Print the output

System.out.print(number % 2);

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.
• The method “foo()” is defined.
- ○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.
- ○ Print the result after determining “number%2”.

Sample Output

Output:

The output is:

10111

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Answer 4

Textbook Question

Chapter 11, Problem 1E

What output will be produced by the following code?

public class Demo

{

public static void main (String[] args)

{

System.out.println (“The output is:”);

foo (23);

System.out. println ();

}

public static void foo (int number)

{

if (number > 0)

{

foo (number / 2);

System.out.print (number % 2);

}

Expert Solution & Answer

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

//Definition of main class

public static void main(String[] args)

{

//Print the statement

System.out.println("The output is:");

//Call the method "foo()"

foo(23);

//Print new line

System.out.println();

}

//Definition of method "foo"

public static void foo(int number)

{

//Check the condition

if (number > 0)

{

//Call the method "foo()"

foo(number / 2);

//Print the output

System.out.print(number % 2);

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.
• The method “foo()” is defined.
- ○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.
- ○ Print the result after determining “number%2”.

Sample Output

Output:

The output is:

10111

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

//Definition of main class

public static void main(String[] args)

{

//Print the statement

System.out.println("The output is:");

//Call the method "foo()"

foo(23);

//Print new line

System.out.println();

}

//Definition of method "foo"

public static void foo(int number)

{

//Check the condition

if (number > 0)

{

//Call the method "foo()"

foo(number / 2);

//Print the output

System.out.print(number % 2);

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.
• The method “foo()” is defined.
- ○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.
- ○ Print the result after determining “number%2”.

Sample Output

Output:

The output is:

10111

Answer 8

Expert Solution & Answer

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

//Definition of main class

public static void main(String[] args)

{

//Print the statement

System.out.println("The output is:");

//Call the method "foo()"

foo(23);

//Print new line

System.out.println();

}

//Definition of method "foo"

public static void foo(int number)

{

//Check the condition

if (number > 0)

{

//Call the method "foo()"

foo(number / 2);

//Print the output

System.out.print(number % 2);

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.
• The method “foo()” is defined.
- ○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.
- ○ Print the result after determining “number%2”.

Sample Output

Output:

The output is:

10111

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

//Definition of main class

public static void main(String[] args)

{

//Print the statement

System.out.println("The output is:");

//Call the method "foo()"

foo(23);

//Print new line

System.out.println();

}

//Definition of method "foo"

public static void foo(int number)

{

//Check the condition

if (number > 0)

{

//Call the method "foo()"

foo(number / 2);

//Print the output

System.out.print(number % 2);

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.
• The method “foo()” is defined.
- ○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.
- ○ Print the result after determining “number%2”.