Chapter 11, Problem 1E

Question

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Answer 1

Expert Solution & Answer

Chapter 11, Problem 1E

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

    //Definition of main class

    public static void main(String[] args)

    {

        //Print the statement

        System.out.println("The output is:");

        //Call the method "foo()"

        foo(23);

        //Print new line

        System.out.println();

    }

    //Definition of method "foo"

    public static void foo(int number)

    {

        //Check the condition

        if (number > 0)

        {

            //Call the method "foo()"

            foo(number / 2);

            //Print the output

            System.out.print(number % 2);

        }

    }

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.

• The method “foo()” is defined.

○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.

○ Print the result after determining “number%2”.

Expert Solution & Answer

Sample Output

Output:

The output is:

10111

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Answer 2

Expert Solution & Answer

Chapter 11, Problem 1E

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

    //Definition of main class

    public static void main(String[] args)

    {

        //Print the statement

        System.out.println("The output is:");

        //Call the method "foo()"

        foo(23);

        //Print new line

        System.out.println();

    }

    //Definition of method "foo"

    public static void foo(int number)

    {

        //Check the condition

        if (number > 0)

        {

            //Call the method "foo()"

            foo(number / 2);

            //Print the output

            System.out.print(number % 2);

        }

    }

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.

• The method “foo()” is defined.

○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.

○ Print the result after determining “number%2”.

Expert Solution & Answer

Sample Output

Output:

The output is:

10111

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Answer 3

Expert Solution & Answer

Chapter 11, Problem 1E

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

    //Definition of main class

    public static void main(String[] args)

    {

        //Print the statement

        System.out.println("The output is:");

        //Call the method "foo()"

        foo(23);

        //Print new line

        System.out.println();

    }

    //Definition of method "foo"

    public static void foo(int number)

    {

        //Check the condition

        if (number > 0)

        {

            //Call the method "foo()"

            foo(number / 2);

            //Print the output

            System.out.print(number % 2);

        }

    }

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.

• The method “foo()” is defined.

○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.

○ Print the result after determining “number%2”.

Expert Solution & Answer

Sample Output

Output:

The output is:

10111

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Expert Solution & Answer

Chapter 11, Problem 1E

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

    //Definition of main class

    public static void main(String[] args)

    {

        //Print the statement

        System.out.println("The output is:");

        //Call the method "foo()"

        foo(23);

        //Print new line

        System.out.println();

    }

    //Definition of method "foo"

    public static void foo(int number)

    {

        //Check the condition

        if (number > 0)

        {

            //Call the method "foo()"

            foo(number / 2);

            //Print the output

            System.out.print(number % 2);

        }

    }

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.

• The method “foo()” is defined.

○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.

○ Print the result after determining “number%2”.

Expert Solution & Answer

Sample Output

Output:

The output is:

10111

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 11, Problem 1E

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

    //Definition of main class

    public static void main(String[] args)

    {

        //Print the statement

        System.out.println("The output is:");

        //Call the method "foo()"

        foo(23);

        //Print new line

        System.out.println();

    }

    //Definition of method "foo"

    public static void foo(int number)

    {

        //Check the condition

        if (number > 0)

        {

            //Call the method "foo()"

            foo(number / 2);

            //Print the output

            System.out.print(number % 2);

        }

    }

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.

• The method “foo()” is defined.

○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.

○ Print the result after determining “number%2”.

Expert Solution & Answer

Sample Output

Output:

The output is:

10111

Answer 8

Chapter 11, Problem 1E

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

    //Definition of main class

    public static void main(String[] args)

    {

        //Print the statement

        System.out.println("The output is:");

        //Call the method "foo()"

        foo(23);

        //Print new line

        System.out.println();

    }

    //Definition of method "foo"

    public static void foo(int number)

    {

        //Check the condition

        if (number > 0)

        {

            //Call the method "foo()"

            foo(number / 2);

            //Print the output

            System.out.print(number % 2);

        }

    }

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.

• The method “foo()” is defined.

○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.

○ Print the result after determining “number%2”.

Expert Solution & Answer

Sample Output

Output:

The output is:

10111

Answer 9

Chapter 11, Problem 1E

Explanation of Solution

Given code:

//Definition of class "Demo"

public class Demo

{

    //Definition of main class

    public static void main(String[] args)

    {

        //Print the statement

        System.out.println("The output is:");

        //Call the method "foo()"

        foo(23);

        //Print new line

        System.out.println();

    }

    //Definition of method "foo"

    public static void foo(int number)

    {

        //Check the condition

        if (number > 0)

        {

            //Call the method "foo()"

            foo(number / 2);

            //Print the output

            System.out.print(number % 2);

        }

    }

}

Explanation:

• In the above code, it calls the method “foo()” in the main class.

• The method “foo()” is defined.

○ Inside the method, it checks the condition “number>0”, if the condition satisfies recursively calls the method “foo()”.

○ Print the result after determining “number%2”.

Answer 10

Expert Solution & Answer

Sample Output

Output:

The output is:

10111

Answer 11

Expert Solution & Answer

Answer 12

Expert Solution & Answer

Answer 13

Chapter 11.1, Problem 1STQ Chapter 11.1, Problem 2STQ Chapter 11.1, Problem 3STQ Chapter 11.1, Problem 4STQ Chapter 11.1, Problem 5STQ Chapter 11.1, Problem 6STQ Chapter 11.2, Problem 7STQ Chapter 11.2, Problem 8STQ Chapter 11.2, Problem 9STQ Chapter 11.2, Problem 10STQ

Chapter 11, Problem 1E

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