The circuit shown has reached steady state before the switch is closed at time t = 0. Determine the inductor current, i(t), for time t > 0. Answer: i(t) = 20-10e-10t (sin(20t) + 2 cos(20t)) mA t=0 w 4000 10V 1000 250μF 10H i(t)

The circuit shown has reached steady state before the switch is closed at time t = 0. Determine the inductor current, i(t), for time t > 0. Answer: i(t) = 20-10e-10t (sin(20t) + 2 cos(20t)) mA t=0 w 4000 10V 1000 250μF 10H i(t)

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter24: Resistive-inductive-capacitive Parallel Circuits

Section: Chapter Questions

Problem 1RQ: An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in...

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Question

Can you show why the answer is that for this question using second order differential equations, instead of laplace transforms

The circuit shown has reached steady state before
the switch is closed at time t = 0. Determine the
inductor current, i(t), for time t > 0.
Answer:
i(t) = 20-10e-10t (sin(20t) + 2 cos(20t)) mA
t=0
w
4000
10V
1000
250μF
10H
i(t)

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