Assume a JFET device with VGS(0) = -1.3 and ipss = 20 mA. Design a self-biased (Fig. 2) JFET common-source amplifier with the gain of -2 and a DC biasing that allows the largest swing in ip. Note that you can choose Vcc to arrive at a desired RD to meet the gain requirement. Since you are designing for a given gain, you may have to check to see if JFET is biased correctly. (Hint: First find Rs for correct VGs and then use the gain to compute RD. Finally, use RD and Rs to determine Vec). Assume that the amplifier is to interface a source that expects a load of 50 2. Also, assume that the amplifier circuit is AC coupled at both ends with 3 dB corner frequency of 15 kHz.
Assume a JFET device with VGS(0) = -1.3 and ipss = 20 mA. Design a self-biased (Fig. 2) JFET common-source amplifier with the gain of -2 and a DC biasing that allows the largest swing in ip. Note that you can choose Vcc to arrive at a desired RD to meet the gain requirement. Since you are designing for a given gain, you may have to check to see if JFET is biased correctly. (Hint: First find Rs for correct VGs and then use the gain to compute RD. Finally, use RD and Rs to determine Vec). Assume that the amplifier is to interface a source that expects a load of 50 2. Also, assume that the amplifier circuit is AC coupled at both ends with 3 dB corner frequency of 15 kHz.
Chapter25: Television, Telephone, And Low-voltage Signal Systems
Section25.1: Television Circuit
Problem 5R: From a cost standpoint, which system is more economical to install: a master amplifier distribution...
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Transcribed Image Text:Assume a JFET device with VGS(0) = -1.3 and ipss = 20 mA. Design a self-biased
(Fig. 2) JFET common-source amplifier with the gain of -2 and a DC biasing that
allows the largest swing in ip. Note that you can choose Vcc to arrive at a desired
RD to meet the gain requirement. Since you are designing for a given gain, you
may have to check to see if JFET is biased correctly. (Hint: First find Rs for correct
VGs and then use the gain to compute RD. Finally, use RD and Rs to determine
Vec). Assume that the amplifier is to interface a source that expects a load of 50
2. Also, assume that the amplifier circuit is AC coupled at both ends with 3 dB
corner frequency of 15 kHz.
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