5'-A-T-G-C-C-T-G-C-A-G-G-T-C-C-A-T-T-G-3' Table 4.5 The genetic code First Position Second Position (5' end) U C A G Third Position (3' end) Phe Ser Tyr Cys U Phe Ser Tyr Cys Leu Ser Stop Stop Leu Ser Stop Trp UCAG Leu Pro His Arg C Leu Pro His Arg Leu Pro Gln Arg Leu Pro Gln Arg UCAC G lle Thr Asn Ser A lle Thr Asn Ser lle Thr Lys Arg Met Thr Lys 22 Arg UCAC G Val Ala Asp Gly G Val Ala Asp Gly Val Ala Glu Gly Val Ala Glu Gly UCAC G Note: This table identifies the amino acid encoded by each triplet. For example, the codon 5'- AUG-3' on mRNA specifies methionine, whereas CAU specifies histidine. UAA, UAG, and UGA are termination signals. AUG is part of the initiation signal, in addition to coding for internal methionine residues. Table 4.5 Blochemistry, Seventh Edition © 2012 W. H. Freeman and Company

5'-A-T-G-C-C-T-G-C-A-G-G-T-C-C-A-T-T-G-3' Table 4.5 The genetic code First Position Second Position (5' end) U C A G Third Position (3' end) Phe Ser Tyr Cys U Phe Ser Tyr Cys Leu Ser Stop Stop Leu Ser Stop Trp UCAG Leu Pro His Arg C Leu Pro His Arg Leu Pro Gln Arg Leu Pro Gln Arg UCAC G lle Thr Asn Ser A lle Thr Asn Ser lle Thr Lys Arg Met Thr Lys 22 Arg UCAC G Val Ala Asp Gly G Val Ala Asp Gly Val Ala Glu Gly Val Ala Glu Gly UCAC G Note: This table identifies the amino acid encoded by each triplet. For example, the codon 5'- AUG-3' on mRNA specifies methionine, whereas CAU specifies histidine. UAA, UAG, and UGA are termination signals. AUG is part of the initiation signal, in addition to coding for internal methionine residues. Table 4.5 Blochemistry, Seventh Edition © 2012 W. H. Freeman and Company

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter9: From Dna To Protein

Section: Chapter Questions

Problem 8SQ

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Below is a sequence of 540 bases from a genome. What information would you use to find the beginnings and ends of open reading frames? How many open reading frames can you find in this sequence? Which open reading frame is likely to represent a protein- coding sequence, and why? Which are probably not functioning protein-coding sequences, and why? Note: for simplicitys sake, analyze only this one strand of the DNA double helix, reading from left to right, so you will only be analyzing three of the six reading frames shown in Figure 19.4.
Codon-Anticodon Recognition: Base-Pairing Possibilities (Integrates with Chapter 11.) Draw base-pair structures for (a) a G:C base pair. (b) a C:G base pair. (C) a G:U base pair, and (d) a U:G base pair. Note how these various base pairs differ in the potential hydrogen-bonding patterns they present within the major groove and minor groove of a double-helical nucleic acid.
How many letters of an RNA molecule, in sequence, does it take to provide the code for a single amino acid? 1 2 3 4
Figure 28.41 gives some examples of recombination in IgG codons 95 and 96, as specified by the Vkand Jkgenes. List the codon possibilities and the amino acids encoded if recombination occurred in codon 97. Which of these possibilities is less desirable?
Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also, write out the amino acid sequence of the protein encoded by this message. tRNA: UAC UCU CGA GGC mRNA: protein: How many hydrogen bonds would be present in the DNA segment?
Using Figures 8.7 and 8.9 as a guide, draw a dinucleotide composed of C and A. Next to this, draw the complementary dinucleotide in an antiparallel fashion. Connect the dinucleotides with the appropriate hydrogen bonds. FIGURE 8.9 The two polynucleotide chains in DNA run in opposite directions. The left strand runs 5 to 3, and the right strand runs 3 to 5. The base sequences in each strand are complementary. An A in one strand pairs with a T in the other strand, and a C in one strand is paired with a G in the opposite strand. FIGURE 8.7 Nucleotides can be joined together to form chains caled polynucleotides. Polynucleotides are polar molecules with a 5 end (at the phosphate group) and a 3 end (at the sugar group). An RNA polynucleotide is shown at the left, and a DNA polynucleotide is shown at the right.
A certain mRNA strand has the following nucleotide sequence: 5AUGACGUAUAACUUU3 What is the anticodon for each codon? What is the amino acid sequence of the polypeptide? (Use Figure 13-5 to help answer this question.) Figure 13-5 The genetic code The genetic code specifies all possible combinations of the three bases that compose codons in mRNA. Of the 64 possible codons, 61 specify amino acids (see Figure 3-17 for an explanation of abbreviations). The codon AUG specifies the amino acid methionine and also signals the ribosome to initiate translation (start). Three codonsUAA, UGA, and UAGdo not specify amino acids; they terminate polypeptide synthesis (stop).
Exploring the Structure of the 30S Ribosomal Subunit Go to www.pdh.org and bring up PDB file 1GIX, which shows the 30S ribosomal subunit, the three tRNAs, and mRNA. In the box on the right titled â€˜Biological Assembly.â€� click â€œMore Images.â€� and then scroll down to look at the Interactive Vic By moving your cursor over the image, you can rotate it to view it from any perspective. a. How are the ribosomal proteins represented in the image? b. How is the 16S rRNA portrayed? c. Rotate the image to see how the tRNAs stick out from the structure. Which end of the tRNA is sticking out? d. Where will these ends of the tRNAs lie when the 50S subunit binds to this complex?
Given the following mRNA, write the double-stranded DNA segment that served as the template. Indicate both the 5 and the 3 ends of both DNA strands. Also write out the tRNA anticodons and the amino acid sequence of the protein encoded by the mRNA message. DNA: mRNA: 5-CCGCAUGUUCAGUGGGCGUAAACACUGA-3 protein: tRNA:
If the genetic code used 4 bases at a time, how many amino acids could be encoded?
Helicase Unwinding of the E. coli Chromosome Hexameric helicases, such as DnaB, the MCM proteins, and papilloma virus El helicase (illustrated in Figures 16.22 to 16.25), unwind DNA by passing one strand of the DNA duplex through the central pore, using a mechanism based on ATP-dependent binding interactions with the bases of that strand. The genome of E. coli K12 consists of 4,686,137 nucleotides. Assuming that DnaB functions like papilloma virus El helicase, from the information given in Chapter 16 on ATP-coupled DNA unwinding, calculate how many molecules of ATP would be needed to completely unwind the E. coli K 12 chromosome.
If the genetic code uses triplets, how many different amino acids can be coded by a repeating RNA polymer composed of UA and UC (UAUCUAUCUAUC ...)? a. one b. two c. three d. four e. five