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12.41 The circuit shown in Fig. P12.41 was introduced in Problem 5.68. Then, a time-domain solution was sought for Dout, (1) and Dout₂ (1) for 10, given that v₁(1) = 10u(t) mV, Vcc 10 V for both op amps, and the two capacitors had no change prior to t = 0. Analyze the circuit and plot Dout, (t) and Dout (1) using the Laplace transform technique. 4μF 5 μF Οι 5 ΚΩ Dout 1 MQ Dout2 + Vcc = 10 V Vec = 10 V Figure P12.41 Circuit for Problems 12.41 and 12.42.

12.41 The circuit shown in Fig. P12.41 was introduced in Problem 5.68. Then, a time-domain solution was sought for Dout, (1) and Dout₂ (1) for 10, given that v₁(1) = 10u(t) mV, Vcc 10 V for both op amps, and the two capacitors had no change prior to t = 0. Analyze the circuit and plot Dout, (t) and Dout (1) using the Laplace transform technique. 4μF 5 μF Οι 5 ΚΩ Dout 1 MQ Dout2 + Vcc = 10 V Vec = 10 V Figure P12.41 Circuit for Problems 12.41 and 12.42.

Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter18: Resistive-inductive Parallel Circuits
Section: Chapter Questions
Problem 13PP: In an R-L parallel circuit, IT=1.25 amps, R=1.2k, and XL=1k. Find IR
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12.41 The circuit shown in Fig. P12.41 was introduced in Problem 5.68. Then, a time-domain solution was sought for Dout, (1) and Dout₂ (1) for 10, given that v₁(1) = 10u(t) mV, Vcc 10 V for both op amps, and the two capacitors had no change prior to t = 0. Analyze the circuit and plot Dout, (t) and Dout (1) using the Laplace transform technique. 4μF 5 μF Οι 5 ΚΩ Dout 1 MQ Dout2 + Vcc = 10 V Vec = 10 V Figure P12.41 Circuit for Problems 12.41 and 12.42.
Transcribed Image Text:12.41 The circuit shown in Fig. P12.41 was introduced in Problem 5.68. Then, a time-domain solution was sought for Dout, (1) and Dout₂ (1) for 10, given that v₁(1) = 10u(t) mV, Vcc 10 V for both op amps, and the two capacitors had no change prior to t = 0. Analyze the circuit and plot Dout, (t) and Dout (1) using the Laplace transform technique. 4μF 5 μF Οι 5 ΚΩ Dout 1 MQ Dout2 + Vcc = 10 V Vec = 10 V Figure P12.41 Circuit for Problems 12.41 and 12.42.
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